AP Physics free response practice help

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sorry for the random letters your responses don't come up on my comp otherwise
 
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wait so would dv/dt just be 8/(1+5t)
 
harmonicmotion said:
sorry for the random letters your responses don't come up on my comp otherwise

I understand.

Now, as for d) assuming you manage c), it is perhaps simplest to remember that the impulse over a time interval equals the change in momentum over that interval.
 
harmonicmotion said:
wait so would dv/dt just be 8/(1+5t)

No, that is v itself!

You must differentiate that expression to get the acceleration.
 
isnt impulse also force times the change in time
 
sorry i still can't figure out c
 
harmonicmotion said:
isnt impulse also force times the change in time
Only if the force is constant.
If it is not constant, you must perform the integral of F over time.
Happily, this equal to the change of momentum over that time.
 
harmonicmotion said:
sorry i still can't figure out c

Well, what is v?

differentiate that function!
 
for c i got (500)(-40)(1+5t)^-2
 
Oops!
Remember that the mass of the system consists of BOTH the masses, i.e, 1000+500=1500.
 
so for 500 i put 1500 and then its right?
 
harmonicmotion said:
so for 500 i put 1500 and then its right?

That is correct.
 
so d is (mv(final)-mv(initial))/(time)
 
No, that would give you the average FORCE over that time interval.
Do not divide with time; the impulse is just the momentum difference.
 
wait sorry i messed up
 
harmonicmotion said:
wait sorry i messed up

Indeed you did.

You should get:

[tex]I=1500*(\frac{8}{11}-8)=-1500*\frac{80}{11}[/tex]
 
oh ok thank you so much!
 
harmonicmotion said:
oh ok thank you so much!

You're welcome! :smile: