Aparant size of an object based on distance from it.

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To determine the apparent size of an object based on distance, a right triangle can be used, where the long side represents the distance from the observer to the object and the short side represents half the object's size. For the Earth, with a diameter of 12,756.1 km viewed from 192,201.5 km away, the angle at the tip of the triangle indicates its apparent size. The discussion emphasizes the use of trigonometry to solve for this angle. Understanding these geometric principles is essential for accurately calculating how large an object appears from a distance. This method can be applied to various objects beyond just the Earth and the Moon.
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Is there an equation I could use to determine how big something would appear to be at a certain distance from said object?

In particular I want to find how big the Earth would appear to be from half way from the Earth to the moon if a picture was taken of it with 1x zoom. in other words, how big would a sphere with a diameter of 12,756.1 km appear from 192,201.5 km away?
 
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Hey Runaway,

It's actually pretty simple. Just draw a long skinny right triangle. The long side of the triangle is the distance between the observer and the object. The short side of the triangle is one-half the size of the object. If you put two of these skinny triangles side by side, you'd make a "cone." The angle at the tip of the cone is the apparent size of the object.

Are you comfortable with the trigonometry involved in solving for the angle?

- Warren
 
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