Aparant size of an object based on distance from it.

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SUMMARY

The discussion focuses on calculating the apparent size of an object based on distance, specifically how large the Earth appears from halfway to the Moon, approximately 192,201.5 km away. The method involves using trigonometry to create a right triangle, where the long side represents the distance to the object and the short side represents half the object's diameter (12,756.1 km). The angle at the tip of the triangle, or cone, represents the object's apparent size. Understanding this geometric relationship is crucial for accurate visual representation in astronomy.

PREREQUISITES
  • Basic understanding of trigonometry
  • Familiarity with right triangles and angles
  • Knowledge of the Earth's diameter (12,756.1 km)
  • Concept of distance measurement in astronomy
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  • Explore the concept of angular size in astronomy
  • Learn about distance measurement techniques in space
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Runaway
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Is there an equation I could use to determine how big something would appear to be at a certain distance from said object?

In particular I want to find how big the Earth would appear to be from half way from the Earth to the moon if a picture was taken of it with 1x zoom. in other words, how big would a sphere with a diameter of 12,756.1 km appear from 192,201.5 km away?
 
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Hey Runaway,

It's actually pretty simple. Just draw a long skinny right triangle. The long side of the triangle is the distance between the observer and the object. The short side of the triangle is one-half the size of the object. If you put two of these skinny triangles side by side, you'd make a "cone." The angle at the tip of the cone is the apparent size of the object.

Are you comfortable with the trigonometry involved in solving for the angle?

- Warren
 

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