1. The problem statement, all variables and given/known data Planet X rotates in the same manner as the earth, around an axis through its north and south poles, and is perfectly spherical. An astronaut who weighs 950.0 N on the earth weighs 919.0 N at the north pole of Planet X and only 855.0 N at its equator. The distance from the north pole to the equator is 1.889×104 Km, measured along the surface of Planet X. 2. Relevant equations g=g0-(v2/r) w=mg v=sqrt(gxpole-gxequatorxrx) 3. The attempt at a solution a)How long is the day on Planet X? Okay so first we need the mass of the astronaught which is we/ge=96.44 Kg. We can then use this to calculate gxequator and gxpole which equal 9.48 m/s^2 and 8.82 m/s^2 respectivly. using the formula g=g0-(v2/r) we can rearrange and solve for v. v=sqrt(gxpole-gxequator*rx) and I get a value of 3530.92 m/s. since v=2pir/T we rearange for T and I get a value of 33614.3 s. Now the answer is incorrect Could anyone please help determine what I'm missing from this question. As always any help is much appreciated.