Applying a Horizontal Stretch to ln(x): Understanding the Shift in f(x)

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Homework Help Overview

The discussion revolves around applying a horizontal stretch to the function f(x) = ln(x) and understanding the implications of such a transformation. Participants are exploring the relationship between horizontal stretches and shifts in the context of logarithmic functions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to relate the concept of horizontal stretching to shifts in the function, with some referencing the laws of logarithms. Questions arise regarding the definitions of "stretch" and "shift" and how they apply to the function f(x).

Discussion Status

The discussion is active, with participants sharing their interpretations and clarifications. There is acknowledgment of differing understandings of horizontal transformations, and some participants are providing insights that may help refine the original poster's conclusions.

Contextual Notes

There is a mention of the need for clarity on the definitions of horizontal stretches versus shifts, as well as the specific conditions under which these transformations are applied (e.g., k > 1). Some participants express uncertainty about how to articulate these concepts clearly.

andrewkg
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Q
Applying a horizontal stretch by a factor of k (where k is a constant such that k>1) to f(x)=lnx is equivalent to applying what shift to f? Give both the amount and direction of the shift.

my A
so i came to the conclusion that the answers must have to do with the laws of logs. and from that i cam to the conclusion the shift = to f(kx)=ln(kx)=ln(x)+ln(k) are = so the shift of f(x) would be f(x)+ln(k).

What do you guys think?
 
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That looks good. Of course, my understanding of what you mean by "stretch" and "shift" is based on the answer you came up with, so it's not like I could look at the problem, solve it and then compare my result to yours.
 


Well vertical shift ment up or down the desired unit. And horazontal stretches and compressions. By the desired factor. Hmm not sure how to put that. Well that basically what the book says.
 
andrewkg said:
Q
Applying a horizontal stretch by a factor of k (where k is a constant such that k>1) to f(x)=lnx is equivalent to applying what shift to f? Give both the amount and direction of the shift.

my A
so i came to the conclusion that the answers must have to do with the laws of logs. and from that i cam to the conclusion the shift = to f(kx)=ln(kx)=ln(x)+ln(k) are = so the shift of f(x) would be f(x)+ln(k).

What do you guys think?

Actually, if k > 1, then f(kx) is a horizontal shrink of f(x) by a factor of 1/k. If you want a horizontal stretch by a factor of k, with k > 1, then you should write it as
[itex]f\left( \frac{x}{k} \right)[/itex].
 
andrewkg said:
Well vertical shift ment up or down the desired unit. And horazontal stretches and compressions. By the desired factor. Hmm not sure how to put that. Well that basically what the book says.
Your answer to the problem gave me more information than that. The horizontal stretch by a factor k is presumably the map ##f\mapsto g## where g is defined by g(x)=f(x/k) for all x.
 
thanks you guys. Once again PF has saved me from a careless error.
 

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