Applying the Weierstrass M test

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SUMMARY

The discussion focuses on applying the Weierstrass M-test to the series \(\sum_{n=1}^{\infty}\frac{1}{n^2}\cos(nx)\) to determine its domain of convergence. The participant identifies the bounding sequence as \(M_n = \frac{1}{n^2}\), which converges. It is established that \(|\frac{1}{n^2}\cos(nx)| \leq \frac{1}{n^2}\), confirming that the series converges uniformly on the entire real line, \(R\).

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Homework Statement



\sum_{n=1}^{\infty}\frac{1}{n^2}cosnx

Apply the Weierstrass M-test to the series in order to find the domain of convergence.

Homework Equations





The Attempt at a Solution



Looking at the functions I think I have gottten to the following conclusion,

f1(x)=cosx <= 1

f2(x)=1/4 cos(2x) <= 1/4

I would pick my sequence to be 1/n^2. I am sure that 1/n^2 converges but does it work as a bound on each term? And then what should I do with these two (the series and the sequence of Mk.)?
 
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I am sure that 1/n^2 converges but does it work as a bound on each term?

Looks like it does

| \frac{1}{n^2} cos(nx) | = \frac{1}{n^2} |cos(nx)|

and |cos(nx)| is always less than or equal to 1.
 
That wasn't too bad. But I have a more specific question. Does the M test say that the domain of convergence is R? Since are sequence of functions is defined on R?
 
Yes. The M test says the series converges uniformly on R, so in particular converges on R.
 

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