Are Momentum Equations Different for Elastic and Inelastic Collisions?

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SUMMARY

This discussion clarifies the equations governing momentum conservation in elastic and inelastic collisions. The correct equations are: for perfectly elastic collisions, both momentum and kinetic energy are conserved, represented as m1u1 + m2u2 = m1v1 + m2v2 and 1/2m1u1^2 + 1/2m2u2^2 = 1/2m1v1^2 + 1/2m2v2^2. In contrast, for perfectly inelastic collisions, only momentum is conserved, expressed as m1u1 + m2u2 = (m1 + m2)v. Understanding these distinctions is crucial for applying the correct principles in physics problems involving collisions.

PREREQUISITES
  • Understanding of linear momentum and its conservation principles
  • Familiarity with kinetic energy and its conservation in physical systems
  • Basic knowledge of elastic and inelastic collision types
  • Ability to manipulate algebraic equations involving mass and velocity
NEXT STEPS
  • Study the principles of conservation of momentum in various collision scenarios
  • Learn the differences between elastic and inelastic collisions in detail
  • Explore real-world applications of momentum conservation in physics
  • Review problem-solving techniques for collision-related physics questions
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of momentum and energy conservation in collisions.

Hanga
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This is not dircectly a coursework question, rather I need someone to tell me what is correct and what is not correct in my assumption of Momentum and collisions, esp conservation of linear momentum.

For some reason I stand to believe there are two diffirent equations for conservation of linear momentum Pbefore=Pafter. In one case we have

m1u1+m2u2 = m1v1m1v2

In the other we have
1/2m1u1^2 + 1/2m2u2^2 = 1/2m1v1^2 + 1/2m2v2^2

For some reson I stand to believe that they are for Perfectly inelastic collisions and Elastic collisions respectivly. Is this the case? Is there some "key word" in a work question that I can look for to say "Ah! I'm going to have use equation x"?
 
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Conservation of momentum is only the first equation you wrote. The second one is the conservation of energy (the expression assumes the potential energy remains constant). Kinetic energy is conserved along with momentum in an elastic collision.
 
Perfectly elastic collisions (Momentum and kinetic energy are both conserved):
m_1 u_1 + m_2 u_2= m_1 v_1 + m_2 v_2 and \frac{1}{2}m_1 u_1^2 + \frac{1}{2}m_2 u_2^2 = \frac{1}{2}m_1 v_1^2 + \frac{1}{2}m_2 v_2^2

Perfectly inelastic collisions (Only momentum is conserved):
m_1 u_1 + m_2 u_2 = (m_1 + m_2) v^2
 

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