Are There Spaces That Are Their Own Automorphisms Group?

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Is there any example of an automorphisms group of a space that coincides with the space, i.e. a space that is its own automorphisms group?
 
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Yes, there are many such examples. if I'm not mistaken ##\mathrm{Aut}(S_n)=S_n## for all ##n## except ##2,6##. But you can check it by hand that ##\mathrm{Aut}(S_3)=S_3##. The groups with this property are called complete groups.
 
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N1k1tA said:
Yes, there are many such examples. if I'm not mistaken [tex]\mathrm{Aut}(S_n)=S_n[/tex] for all [tex]n[/tex] except [tex]2,6[/tex]. But you can check it by hand that [tex]\mathrm{Aut}(S_3)=S_3[/tex]. The groups with this property are called complete groups.
Thanks, I was under the impression that the isometry group of ##S^3## was ##SO(4)##.
 
TrickyDicky said:
Thanks, I was under the impression that the isometry group of ##S^3## was ##SO(4)##.

##S^3## is the ##3##-sphere (the ##3##-dimensional sphere embedded in ##\mathbb{R}^4##), while ##S_3## is the group of permutations on ##3## letters. Totally different things.

Does your problem concern Lie groups or any arbitrary groups?
 
N1k1tA said:
##S^3## is the ##3##-sphere (the ##3##-dimensional sphere embedded in ##\mathbb{R}^4##), while ##S_3## is the group of permutations on ##3## letters. Totally different things.

Does your problem concern Lie groups or any arbitrary groups?
Oh, sorry, I should have made clear I referred to continuous spaces and groups.