MHB Are you smarter than a Singaporean 10 year old?

  • Thread starter Thread starter GLONE007
  • Start date Start date
  • Tags Tags
    Year
AI Thread Summary
The discussion revolves around a math problem from The Guardian that challenges readers to determine the length of remaining string after specific cuts. The problem states that Mary cut off 2/5 of a string and later removed another 14 meters, with the remaining string's length to the total cut off being in a ratio of 1:3. A step-by-step breakdown of the solution is provided, leading to the conclusion that the original length of the string is 40 meters, resulting in 10 meters remaining after the cuts. Participants express confusion and seek clarification on the solution process, emphasizing a desire for a clearer understanding. The thread illustrates the challenge of grasping mathematical concepts presented in a problem-solving context.
GLONE007
Messages
1
Reaction score
0
So i was looking through The Guardian(newspaper) and found this question, Titled 'are you smarter then a 10 year old?' and as you can guess i had no clue what to do. Also i thought if i looked at the answer maybe i would realize how it worked. Oh. how wrong was I! Is anyone able to break it down even more?. so that someone like 'me' can understand how it is done and how it works.

1. Mary cut off 2/5 of a piece of string. Later, she cut off another 14 m. The ratio of the length of string remaining to the total length cut off is 1 : 3. What is the length of the remaining string?

A. 5 m
B. 7 m
C. 10 m
D. 14 m
Solution is C.

I saw two ways of doing this yet they both through me off, i was wondering if someone could. in a sense talk it through step by step.As i am determined to understand how it works.

Many thanks.
 
Mathematics news on Phys.org
Re: Are you smarter then a Singaporean 10 year old?

what we wind up with is (where $\ell$ is the original length in m):

$$0.6\ell-14=\frac{1}{3}\left(0.4\ell+14\right)$$

$$1.8\ell-42=0.4\ell+14$$

$$1.4\ell=56$$

$$\ell=40$$

Hence:

$$\frac{3}{5}40-14=24-14=10$$

edit: I've moved this thread here, as it's a better fit.
 
I believe I can explain it well, because tbh is quite easy to understand if you check out my way. The simplest thing you could've done is to express the total length of the string. You can use any letter you want, but usually l stands for length in Maths as Mark has used.

\ell=
 
Last edited:
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...
Thread 'Unit Circle Double Angle Derivations'
Here I made a terrible mistake of assuming this to be an equilateral triangle and set 2sinx=1 => x=pi/6. Although this did derive the double angle formulas it also led into a terrible mess trying to find all the combinations of sides. I must have been tired and just assumed 6x=180 and 2sinx=1. By that time, I was so mindset that I nearly scolded a person for even saying 90-x. I wonder if this is a case of biased observation that seeks to dis credit me like Jesus of Nazareth since in reality...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
Back
Top