Area between two trigonometric curves.

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Discussion Overview

The discussion revolves around finding the area between two trigonometric curves, specifically the functions \( y = \frac{\csc^2{x}}{4} \) and \( y = 4\sin^2{x} \). The context is homework-related, with participants exploring the necessary steps to solve the problem, including determining the bounds and setting up the integral.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant mentions that their professor allows them to seek help as long as they are not just receiving final answers without effort.
  • Another participant suggests that the area can be calculated using the integral \( \int^b_a[f(x)-g(x)]dx \) and provides a specific integral setup based on the identified bounds.
  • A participant expresses uncertainty about the roots they found, stating they believe the intersections occur at \( x = \frac{\pi}{6} \) and \( x = \frac{5\pi}{6} \).
  • There is a note that the functions will continue to intersect, indicating the need for careful consideration of the domain when calculating the area.
  • Participants encourage the original poster to walk through their work on the integral to avoid potential mistakes.

Areas of Agreement / Disagreement

Participants generally agree on the need to establish bounds for the integral and the approach to finding the area, but there is uncertainty regarding the correctness of the identified roots and the implications of the functions' intersections.

Contextual Notes

There are limitations regarding the assumptions made about the intersections of the functions and the potential for multiple regions of area due to their periodic nature. The discussion does not resolve these complexities.

alane1994
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http://www.mathhelpboards.com/f12/im-clueless-how-start-2322/
My math class uses an online homework system. I got the answer wrong to the question, but I can get a similar question. Here is one that is similar to the earlier one.

You have two functions that are graphed.
y=\frac{\csc^2{x}}{4}
y=4\sin^2{x}

The purpose of the problem is to find the area between the curves.
 
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Re: Related to clueless

1) If you bring up that this is homework you also should state your professor is ok with you receiving guidance as long as you aren't just getting final answers without any effort. If you don't express this it could come off as cheating and waste time explaining this to the moderators after the fact.

2) What have you tried so far? This is going to be an integral and from the other thread we've already established the bounds, so show us what you've done.

This is not meant to be rude, just some advice on how you can get help the fastest and in the most efficient way for everyone :)
 
Re: Related to clueless

1) OK, my professor is OK with me getting help as long as I am not just getting answers.
2) I have done the roots so far... I believe they are
x=\frac{\pi}{6},\frac{5\pi}{6}
Although, I am not too confident in this answer...
 
Re: Related to clueless

Then
\text{Area}=\int^b_a[f(x)-g(x)]dx

\text{Area}=\int^\frac{5\pi}{6}_\frac{\pi}{6}[4\sin^2{x}-\frac{\csc^2{x}}{4}]dx
 
Re: Related to clueless

Again we need a domain because of these two functions will keep intersecting but assuming the question is looking for the area of one of these regions then one pair of lower and upper bounds is indeed [math]\left[ \frac{\pi}{6},\frac{5\pi}{6} \right][/math]. Your integral looks good. If you're doing it by hand then this calculation has a lot of room for mistakes. Walk us through your work on the integral now.
 

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