Area command in Matlab or Mathematica or Maple

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SUMMARY

The discussion focuses on calculating the area of a closed curve using commands in Matlab, Mathematica, or Maple. Users specifically mention the equation of a circle, x^2 + y^2 = 1, and seek a straightforward command to compute the area, ideally without manually determining intersection points. In Mathematica, the use of the commands RegionPlot and Integrate with Boole[] or Piecewise[] functions is recommended for efficient area calculation. This approach allows for the integration of regions defined by boolean expressions, significantly improving performance.

PREREQUISITES
  • Familiarity with Mathematica syntax and functions
  • Understanding of integral calculus and area under curves
  • Knowledge of boolean expressions in mathematical programming
  • Experience with region plotting in Mathematica
NEXT STEPS
  • Explore the Integrate function in Mathematica for area calculations
  • Learn about RegionPlot for visualizing mathematical regions
  • Research the performance differences between Boole[] and Piecewise[] in Mathematica
  • Investigate similar area calculation commands in Matlab and Maple
USEFUL FOR

Mathematicians, data scientists, and engineers who require efficient methods for calculating areas of closed curves in computational environments like Mathematica, Matlab, or Maple.

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Hi,
I would like to know if there is a command in Matlab or Mathematica or Maple, which shows the area of a closed curve.
For example, find the area enclosed by a circle, x^2+y^2=1.
I wish I could use a command like "SOME_AREA_COMMAND[x^2+y^2=1]" and it can give me the answer Pi.

I know I can use integral, but sometimes it is difficult to find the joint points.

Thank you all. :-)
 
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For Mathematica:region = x^2 + y^2 < 1 && x > 0;
RegionPlot[region, {x, -2, 2}, {y, -2, 2}]
Integrate[If[region, 1, 0], {x, -1, 1}, {y, -1, 1}]is for a half circle. so long as its bounded i believe this will work for all regions that you want without finding the limits of curves.So long as you can write this as a boolean of a closed function (being inside or out) this should work.
 
I agree with Hepth's reply, except that it's preferable to use Boole[] or Piecewise[] for algebra/symbolics and keep If[] for programming constructs. They former are better integrated into the Integrate function and run faster (about 10 times faster on my machine)

Integrate[Boole[region], {x, -1, 1}, {y, -1, 1}]

Integrate[Piecewise[{{1, region}}, 0], {x, -1, 1}, {y, -1, 1}]
 

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