Petrus
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Hello MHB,
Decide area of the two function
$$y^2=x+1$$ and $$y=-x+1$$
progress:
first I equal them to see where they intercept and get $$x=0$$ and $$x=3$$
then I do integrate
$$\int_0^3 \sqrt{x+1}-(-x+1) = \frac{37}{6}$$ which is not correct answer, What I am doing wrong?
Regards,
$$|\pi\rangle$$
Decide area of the two function
$$y^2=x+1$$ and $$y=-x+1$$
progress:
first I equal them to see where they intercept and get $$x=0$$ and $$x=3$$
then I do integrate
$$\int_0^3 \sqrt{x+1}-(-x+1) = \frac{37}{6}$$ which is not correct answer, What I am doing wrong?
Regards,
$$|\pi\rangle$$