# Homework Help: Area Under The Graph (Quick Question)

1. Oct 13, 2006

### Incog

So I have a velocity-time graph and I need to calculate the area under it. I guess the "shape" made is a triangle so the formula would be 0.5 x b x h. But what exactly is the area under the graph supposed to represent? Does it have anything to do with position?

2. Oct 13, 2006

### chuy

If the function of you graphic is f(x), the area is:

$$A=\int f(x) dx$$

If f(x)=mx +b :

$$A=\int (mx +b)dx$$

$$A= \frac{1}{2}mx^2+bx$$

See: http://en.wikipedia.org/wiki/Integral

I hope to have helped

3. Oct 13, 2006