Arhenius equation solving for K1/T2

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SUMMARY

The discussion focuses on solving the Arrhenius equation for K2 or T2 using the formula ln(K1/K2) = Ea/R(1/T1) - (1/T2). The user attempts to isolate K2 in the equation ln(23/x) = 139J/8.314J(1/750) - (1/800) but struggles to achieve the correct answer, which the professor indicates is 6.07. The conversation emphasizes the need for algebraic manipulation to isolate the desired variable.

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lazybone
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Hey guys its my first time in this forum and I need help with my chemistry. I guess its kind if basic chem. Basically its a question to solve for K2 or T2. Like I'm not sure how to isolate the k or T.


Homework Statement




Homework Equations



ln(K1/K2)=Ea/R(1/T1)-(1/T2)

Ln(23/x)=139J/8.314J(1/750)-(1/800)


The Attempt at a Solution



I keep getting a different answer than the real one . My professor said it is 6.07. Please help I'm not sure how to isolate the K2. And what happens if I need to find T2. Thanks
 
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Use simple Algebra to solve this. Show some work on how you tried to isolate it, and I will then guide you on how to figure it out.
 
lazybone said:

Homework Equations



ln(K1/K2)=Ea/R(1/T1)-(1/T2)

Ln(23/x)=139J/8.314J(1/750)-(1/800)

The equation is: ln(K1/K2)=Ea/R[(1/T1)-(1/T2)]
 

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