Which Arrhenius Equation Version Is Correct?

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SUMMARY

The discussion centers on the correct formulation of the Arrhenius Equation for calculating activation energy (Ea). Two versions are presented: ln(k2/k1) = -Ea/R * (1/T2 - 1/T1) and ln(k1/k2) = Ea/R * (1/T2 - 1/T1). Both equations are mathematically equivalent due to the properties of logarithms, specifically ln(a/b) = ln a - ln b. Therefore, users can confidently use either version depending on their preference for the sign of Ea.

PREREQUISITES
  • Understanding of the Arrhenius Equation
  • Familiarity with thermodynamic concepts
  • Basic knowledge of logarithmic properties
  • Experience with activation energy calculations
NEXT STEPS
  • Study the derivation of the Arrhenius Equation
  • Explore the implications of activation energy in chemical kinetics
  • Learn about temperature dependence in reaction rates
  • Investigate the role of the gas constant (R) in thermodynamic equations
USEFUL FOR

Chemists, chemical engineers, and students studying reaction kinetics or thermodynamics will benefit from this discussion.

jaydnul
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When finding the activation energy, which equation is the correct one:

ln(k2/k1)=-Ea/R * (1/T2-1/T1)
or
ln(k1/k2)=Ea/R * (1/T2-1/T1)

Notice k1/k2 in the second equation. As well as the -Ea instead of Ea

Thanks
 
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Aren't they both the same? ln(a/b) = ln a - ln b = -(ln b - ln a) = -ln(b/a) ?
 

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