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Chemistry- two point Arrhenius Equation (miscalculation?)

  1. Jan 25, 2009 #1
    Chemistry- two point Arrhenius Equation (miscalculation??)

    1. The problem statement, all variables and given/known data

    At 25 degrees celsius, the first-order rate constant for a reaction is 2.0 x 10^3 s^-1. The activation energy is 15.0 kJ/mol. what is the value of the rate constant at 75 degrees celsius.

    T1= 298.15 K
    T2= 348.15 K
    K1= 2.0 x 10^3 s^-1
    Ea= 15.0 kJ/mol
    K2= ??


    2. Relevant equations

    K2=K1(e^[(Ea/R)(1/T1-1/T2)])


    3. The attempt at a solution

    K2= 2.0 x 10^3 s^-1(e^[(15.0 kJ/mol / 8.3145 J/molK)(10^3 J / 1 kJ)(0.0036 K - 0.0029 K)])

    I can't remember if the solution is supposed to be 4.8 x 10^3 s^-1. This is taken from my notes that I have on my course guide. I am basically trying to replicate the entire process, but I keep coming up with over sized answers that are to the 9th power or something.... -.-
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Jan 26, 2009 #2
    Re: Chemistry- two point Arrhenius Equation (miscalculation??)

    lol i cant understand your work...try using the super and subscripts and latex...then maybe people can read what you're trying to say
     
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