Arithmetic problem: What is the capacity of each Breaker"?

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SUMMARY

The arithmetic problem involves calculating the capacity of beakers containing oil and water, given that there are 6 beakers of oil and 12 beakers of water, totaling 66 liters. The equation derived from the problem is 6O + 12W = 66, which simplifies to O + 2W = 11. This equation yields multiple integer solutions for the capacities of the beakers, specifically (O, W) pairs such as (1, 5), (3, 4), (5, 3), (7, 2), and (9, 1).

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Need help with this
I have 6 beaker of oil and 12 breaker of water, the total amount combined are 66 litres .
What is the capacity of each Breaker"?
 
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Without more information, we will get an infinite number of ordered pairs that will satisfy the problem. I am assuming that the beakers containing oil all have the same capacity, and the beakers containing water all have the same capacity...and if we let $O$ be the capacity of the beakers containing oil, and $W$ be the capacity of the beakers containing water, we may state:

$$6O+12W=66$$

Divide through by 6:

$$O+2W=11$$

Even if we restrict ourselves to the positive integers, we have numerous solutions:

$$(O,W)=(1,5),\,(3,4),\,(5,3),\,(7,2),\,(9,1)$$
 

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