MHB Arithmetic problem: What is the capacity of each Breaker"?

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The problem involves finding the capacity of beakers containing oil and water, given that there are 6 beakers of oil and 12 of water, totaling 66 liters. The equation derived from the scenario is 6O + 12W = 66, which simplifies to O + 2W = 11. This equation allows for multiple solutions, even when restricted to positive integers. Examples of possible capacities include (1,5), (3,4), (5,3), (7,2), and (9,1). The discussion highlights the need for additional constraints to determine a unique solution.
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I have 6 beaker of oil and 12 breaker of water, the total amount combined are 66 litres .
What is the capacity of each Breaker"?
 
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Without more information, we will get an infinite number of ordered pairs that will satisfy the problem. I am assuming that the beakers containing oil all have the same capacity, and the beakers containing water all have the same capacity...and if we let $O$ be the capacity of the beakers containing oil, and $W$ be the capacity of the beakers containing water, we may state:

$$6O+12W=66$$

Divide through by 6:

$$O+2W=11$$

Even if we restrict ourselves to the positive integers, we have numerous solutions:

$$(O,W)=(1,5),\,(3,4),\,(5,3),\,(7,2),\,(9,1)$$
 
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