Arithmetic Progression Problem

Click For Summary
SUMMARY

The discussion revolves around solving an arithmetic progression problem where the sum of the first 7 terms is 28 and the sum of the first 15 terms is 90. The key equations used are Sn = 0.5n[2a+(n-1)d] for the sum of n terms, where 'a' is the first term and 'd' is the common difference. The solution reveals that the common difference 'd' is 7.75 and the first term 'a' is -18.5. The final expression for the sum of n terms is derived as Sn = n/4(n + 9).

PREREQUISITES
  • Understanding of arithmetic progression and its properties
  • Familiarity with the formula for the sum of n terms, Sn = 0.5n[2a+(n-1)d]
  • Basic algebraic manipulation skills
  • Knowledge of solving linear equations
NEXT STEPS
  • Study the derivation of the formula for the sum of an arithmetic progression
  • Practice solving problems involving arithmetic sequences and series
  • Explore the application of arithmetic progressions in real-world scenarios
  • Learn about geometric progressions and their differences from arithmetic progressions
USEFUL FOR

Students studying mathematics, particularly those focusing on sequences and series, as well as educators looking for examples of arithmetic progression problems.

z.js
Messages
57
Reaction score
0

Homework Statement


If the sum of the first 7 terms of an arithmetic progression is 28 and the sum of the first 15 terms is 90, find the sum of n terms.:eek:


Homework Equations


Sn = 0.5n[2a+(n-1)d]
a is the first term and d is the common difference. n is the number of terms.
nth term = a + (n-1)d


The Attempt at a Solution


(here goes :rolleyes:)
(1)...a + 6d = 28
(2)...a + 14d = 90
(2)-(1)...8d = 62
...d = 7.75 (ok :cool:)
(1)...a + 6(7.75) = 28
.....a = -18.5 (yea! :biggrin:)
(drumrollllllllllll)
Sn = 0.5n(-37 + (n-1)7.75)
= -18.5n +n(n-1)3.875
= n[3.875(n-1) - 18.5] :approve:
...:mad: now what? the answer was n/4(n + 9)
 
Physics news on Phys.org
z.js said:

Homework Statement


If the sum of the first 7 terms of an arithmetic progression is 28 and the sum of the first 15 terms is 90, find the sum of n terms.:eek:

Homework Equations


Sn = 0.5n[2a+(n-1)d]
a is the first term and d is the common difference. n is the number of terms.
nth term = a + (n-1)d

The Attempt at a Solution


(here goes :rolleyes:)
(1)...a + 6d = 28
(2)...a + 14d = 90
(2)-(1)...8d = 62
...d = 7.75 (ok :cool:)
(1)...a + 6(7.75) = 28
.....a = -18.5 (yea! :biggrin:)
(drumrollllllllllll)
Sn = 0.5n(-37 + (n-1)7.75)
= -18.5n +n(n-1)3.875
= n[3.875(n-1) - 18.5] :approve:
...:mad: now what? the answer was n/4(n + 9)

You have used formula of the nth term instead of using that of sum of n terms .28 is not the 7th term .Instead it is the sum of first 7 terms .Similarly with 90 being the sum of first 15 terms.

Use Sn = (n/2)[2a+(n-1)d]
 
Last edited:
ahh! I forgot! thanks
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
4
Views
2K
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K