Arithmetic Sequence Homework: Find the Sum

Click For Summary

Homework Help Overview

The discussion revolves around a problem involving arithmetic sequences, specifically focusing on deriving formulas for the sums of various types of progressions, including arithmetic and double arithmetic progressions, as well as factorial progressions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the derivation of the sum of the first n terms of an arithmetic progression and express confusion regarding the application of formulas in specific cases. There is an exploration of the relationships between terms in double arithmetic progressions and factorial progressions, with attempts to establish explicit formulas.

Discussion Status

Some participants have successfully derived a formula for the sum of the first n terms of an arithmetic progression but are seeking further guidance on the double arithmetic progression. There is acknowledgment of a misunderstanding regarding the expected results when substituting values into the formulas, and participants are actively engaging with each other's insights.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can share or the methods they can use. There is a focus on ensuring clarity in the definitions and setups of the sequences involved.

FeDeX_LaTeX
Science Advisor
Messages
436
Reaction score
13

Homework Statement



This is taken from STEP I 1990, Q4.

(i) The sequence a1, a2, ..., an, ... forms an arithmetic progression. Establish a formula, involving n, a1, and a2, for the sum of the first n terms.

(ii) A sequence b1, b2, ..., bn, ... is called a double arithmetic progression if the sequence of differences, b2 - b1, b3 - b2, ..., bn+1 - bn, ... is an arithmetic progression. Establish a formula, involving n, b1, b2 and b3, for the sum b1 + b2 + ... + bn of the first n terms of such a progression.

(iii) A sequence c1, c2, ..., cn, ... is called a factorial progression if cn+1 - cn = n!d, for some non-zero d and every n ≥ 1. Suppose 1, b2, b3, ... is a double arithmetic progression, and also that b2, b4, b6 and 220 are the first four terms in a factorial progression. Find the sum 1 + b1 + b2 + ... + bn.

Homework Equations



Standard arithmetic progression formulae below

The nth term of an AP: un = a + (n-1)d
The sum of the first n terms of an AP: Sn = (n/2)(a + l) = (n/2)(2a + (n-1)d)

The Attempt at a Solution



I've done (i) quite comfortably and got

\frac{n}{2}((3-n)a_{1} + (n-1)a_{2})

However, (ii) is where I get stuck. By considering the sequence of differences, I've established that

b_n = a + (n-2)d + b_{n-1}

with a = b2 - b1, and d = (b3 - b2) - (b2 - b1). Can anyone guide me on where to go next?
 
Last edited:
Physics news on Phys.org
FeDeX_LaTeX said:
I've done (i) quite comfortably and got

\frac{n}{2}((3-n)a_{1} + (n-1)a_{2})
With n=2, I get a1+a2, but the result should be a2.

Can anyone guide me on where to go next?
An explicit formula for bn could be useful. In your formula, you can express bn-1 in terms of bn-2 and so on, until you reach b1.
 
mfb said:
With n=2, I get a1+a2, but the result should be a2.

Why? We were looking for the sum of the first n terms. With n = 2, that is a1 + a2.

An explicit formula for bn could be useful. In your formula, you can express bn-1 in terms of bn-2 and so on, until you reach b1.

Ah I see, thanks. I will try this and reply if I get the correct result.
 
FeDeX_LaTeX said:
Why? We were looking for the sum of the first n terms. With n = 2, that is a1 + a2.
Yes, you were correct, FeDeX_LaTeX .
 
Oh sorry, I did not see that (a) should be a sum of the first n terms as well.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 10 ·
Replies
10
Views
3K
Replies
4
Views
2K
Replies
3
Views
5K