Arithmetic progression question

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Homework Help Overview

The problem involves an arithmetic series where the sum of the first n even-numbered terms exceeds the sum of the first n odd-numbered terms by 4n. The objective is to find the common difference of the series.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the distinction between the sum of even terms and the sum of even-numbered terms, suggesting a need to clarify definitions. There are attempts to express the sums in terms of the first term and the common difference. Some participants propose defining new sequences for odd and even terms to facilitate calculations.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations and approaches to formulating equations. Some guidance has been offered regarding how to express the sums and set up the equations, but there is no explicit consensus on a method yet.

Contextual Notes

Participants express difficulty in forming appropriate equations and clarifying the definitions of terms involved in the problem. The original poster's request for help indicates a lack of initial ideas or direction.

Michael_Light
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Homework Statement



Series Q is an arithmetic series such that the sum of its first n even terms is more than the sum of its first n odd terms by 4n. Find the common difference of the series Q. The answer provided is 4.

Homework Equations


The Attempt at a Solution



I have no ideas on this... Can you help me?
 
Last edited:
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You don't mean the sum of the even terms, you mean the even numbered terms. The sum of the first n even numbered would be:

a2+a4+...a2n

and the odd would be

a1+a3+...a2n-1

Write both sums in terms of a1 and the unknown d and use your given equation that one is 4n larger than the other.
 
LCKurtz said:
You don't mean the sum of the even terms, you mean the even numbered terms. The sum of the first n even numbered would be:

a2+a4+...a2n

and the odd would be

a1+a3+...a2n-1

Write both sums in terms of a1 and the unknown d and use your given equation that one is 4n larger than the other.

I have difficulty on forming an appropriate equation to find the common difference... can you help me..?
 
I found it easier to define two new sequences, b, and c,
where b contains the odd-numbered terms of sequence a, and
where c contains the even-numbered terms of sequence a.

So, for sequence b:
b1 = a1
b2 = a3 = a1 + 2d
b3 = a5 = a1 + 4d
bn = a(2n-1) = ?

Then find the sum of the first n terms of sequence b. Repeat the process for sequence c. Then plug into
(sum of n terms in seq. b) + 4n = (sum of n terms in seq. c)
and solve for d.
 
If the common difference between terms in the original series is d, then the series of odd indexed terms and the series of even indexed terms are arithmetic series with common difference 2d.
 

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