MHB Arithmetic Sequence Confusion // a{n-1} and a{n+1}

AI Thread Summary
The discussion centers on understanding the arithmetic sequence defined by a{0}=2 and the recurrence relation a{n+1}=3a{n}−1. Participants clarify that to find a{3}, one must first calculate a{1} and a{2} using the previous terms. The confusion arises from interpreting the relationship between a{n} and a{n+1}, with some mistakenly thinking it implies using the next term instead of the current one. Ultimately, the correct approach involves sequentially applying the recurrence relation to derive the values, leading to the conclusion that a{3}=41.
Machara
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So I have this problem I'm stuck on wrapping my head around a particular problem "In the sequence a{n}, let a{0}=2. If a{n+1} = 3 a{n} −1, then what is the value of a3?"

I understand it's following the pattern of each term, and that with Arithmetic sequence a{n-1} means you would use the a{n} term immediately prior (e.g solving for a{2} you would use the result of a{1}) but in this particular problem the sequence is a{n+1} which one would assume you would use the result of the term after? since it's Plus 1 not Minus 1, but that doesn't make sense.

On top of I can elaborate the solutions answer on my worksheet to explain what's happening, and it's saying for a{2} you would input the solution from a{1} to solve for a{2} but wouldn't that be implying the sequence is a{n-1} not a{n+1}?

What's the difference? am I missing something?
This is the elaborated solution that the webpage answers for me:

"Explanation:

To find a{3}
, first find a{1} and a{2}. The sequence says a(n+1)=3a{n}−1, and we know a{0}=2. So, we can find the rest of the sequence, starting with a{1}

.
a{0}=2
a{1}=3(2)−1=5
a{2}=3(5)−1=14
a{3}=3(14)−1=41

So, a{3}=41"
 
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Machara said:
So I have this problem I'm stuck on wrapping my head around a particular problem "In the sequence a{n}, let a{0}=2. If a{n+1} = 3 a{n} −1, then what is the value of a3?"
Do you understand what "a{0}= 2, a{n+1}= 3a{n}- 1" means?

You are told that a{0}= 2. a{1}= a{0+ 1} so a{1}= 3a{0}- 1= 3(2) -1= 5. Then a{2}= a{1+ 1}= 3a{1}- 1= 3(5)- 1= 15- 1= 14. Finally, a{3}= a(2+ 1}= 3a(2)- 1= 3(14)- 1= 42- 1= 4.

I understand it's following the pattern of each term, and that with Arithmetic sequence a{n-1} means you would use the a{n} term immediately prior (e.g solving for a{2} you would use the result of a{1}) but in this particular problem the sequence is a{n+1} which one would assume you would use the result of the term after? since it's Plus 1 not Minus 1, but that doesn't make sense.

On top of I can elaborate the solutions answer on my worksheet to explain what's happening, and it's saying for a{2} you would input the solution from a{1} to solve for a{2} but wouldn't that be implying the sequence is a{n-1} not a{n+1}?
I have no idea where you got "a-1". The problem clearly says a{n+1}

What's the difference? am I missing something?
This is the elaborated solution that the webpage answers for me:

"Explanation:

To find a{3}
, first find a{1} and a{2}. The sequence says a(n+1)=3a{n}−1, and we know a{0}=2. So, we can find the rest of the sequence, starting with a{1}

.
a{0}=2
a{1}=3(2)−1=5
a{2}=3(5)−1=14
a{3}=3(14)−1=41

So, a{3}=41"
I don't see what you could be misunderstanding about this. They took each "a" value, in turn, and calculated 3a(n)- 1 to find the next "a".
 
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