Artificial Gravity in a space station

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Homework Help Overview

The discussion revolves around the concept of artificial gravity in a rotating space station, specifically focusing on the calculations related to the radii of chambers and the simulated acceleration due to gravity. The problem involves understanding the relationships between linear velocity, radius, and acceleration in a rotational context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of given equations to find the radii and acceleration. Some express confusion about how to manipulate the equations effectively, while others suggest finding the period of rotation or linear velocity as a starting point.

Discussion Status

There is ongoing exploration of the equations and their meanings, with some participants providing clarifications on the relationships between variables. One participant indicates progress in solving the problem after recognizing a misunderstanding of the period of rotation.

Contextual Notes

Participants mention the need to submit answers by a deadline, which adds urgency to their inquiries. There is also a reference to the challenges of learning in an online class environment, which may influence the depth of understanding and engagement in the discussion.

jacksonpeeble
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Homework Statement


To create artificial gravity, the space station shown in the drawing is rotating at a rate of 1.10 rpm. The radii of the cylindrically shaped chambers have the ratio rA/rB = 3.85. Each chamber A simulates an acceleration due to gravity of 10.0 m/s2.

05_36.gif


(a) Find rA.
(b) Find rB.
(c) Find the acceleration due to gravity that is simulated in chamber B.

Homework Equations


aA=vA2/rA
rA=aAT2/(4pi2)
aB=4pirB/T2

The Attempt at a Solution


Obviously, we have the information that the problem statement gave. Also, t=60. When problem (a) is found, that would just have to be divided by 3.85 to get the next answer, as well. However, I do not understand how to apply the formulas that I have been given to yield answers.

Thank you in advance for any help!
 
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You can either find the period of rotation or the linear velocity at rA. Use those in the equations you gave with aA being the acceleration.
 
I do not understand how to apply the equations. Detailed help would be greatly appreciated.

I do need to turn these answers into my online class (online math classes are awful in my opinion, it's so hard to learn from them) by midnight, but I would also like to understand.
 
From what it sounds like, your problem is the actual understanding of what each equation means.

aA=VA2/rA

This gives the acceleration (aA) from the linear velocity (VA) and the radius of rotation (rA).

rA=aAT2/(4pi2)

This gives the radius of rotation (rA) from the acceleration (aA) and the period of rotation (T).

aB=4pi (rB/T2)

This gives the acceleration (aB) from the radius of rotation (rB) and the period of rotation (T).
 
For the first equation, what are the values that go along with the variables?

For example, as mentioned, T=60.

aA=? (shouldn't it be equal to 10)
VA=?
rA=?
 
jacksonpeeble said:
For example, as mentioned, T=60.

I don't see how you are getting T=60.

aA=? (shouldn't it be equal to 10)

Yes. But don't forget your units.

VA=?

This is something that you would need to find.

rA=?

This is what the problem is asking for.

One thing to note, you don't have to use the equations in the order they are given, nor do they have to be in the form they are given. You can algebraically manipulate them to find the terms you need.
 
Thanks for all of your help! I was able to solve all parts of the question because you pointed out that I was incorrect. I was accidentally using the value for 1 rpm, which would be 60.

T=60*1.1=66

This messed up the combined equation that I was attempting to use, and all of the others, leading me to believe that I misunderstood the variables.
 
jacksonpeeble said:
T=60*1.1=66

Double check your units, you have T = (1.1 rev/min) * (60 sec/min) = 66 rev*sec/min2.

What it should be is Freq = (1.1 rev/min) * (1 min/60sec) = 1.1 rev/60 sec with T = 1/Freq, making T = 60 sec/1.1 rev.
 

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