[ASK] A Line Intercepting A Circle

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Monoxdifly
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A circle whose center is (2, 1) intercepts a line whose equation is 3x + 4y + 5 = 0 at point A and B. If the length of AB = 8, then the equation of the circle is ...
A. $$x^2+y^2-24x-2y-20=0$$
B. $$x^2+y^2-24x-2y-4=0$$
C. $$x^2+y^2-12x-2y-11=0$$
D. $$x^2+y^2-4x-2y+1=0$$
E. $$x^2+y^2-4x-2y+4=0$$

I don't know how to do it. Judging by the center of the circle, the answer must be either D or E. However, when I checked both of them with Desmos, neither circles even touches the line. How should I do it? Even if there's no right option, I would still like to know in case I encounter this kind of question again.
 
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Monoxdifly said:
A circle whose center is (2, 1) intercepts a line whose equation is 3x + 4y + 5 = 0 at point A and B. If the length of AB = 8, then the equation of the circle is ...
A. $$x^2+y^2-24x-2y-20=0$$
B. $$x^2+y^2-24x-2y-4=0$$
C. $$x^2+y^2-12x-2y-11=0$$
D. $$x^2+y^2-4x-2y+1=0$$
E. $$x^2+y^2-4x-2y+4=0$$

I don't know how to do it. Judging by the center of the circle, the answer must be either D or E. However, when I checked both of them with Desmos, neither circles even touches the line. How should I do it? Even if there's no right option, I would still like to know in case I encounter this kind of question again.
https://www.desmos.com/calculator/ngflni4a1s
 
Find the distance $h$ from the circle center $O$ to the line using this formula. Then you have an isosceles triangle with base $AB=8$ and height $h$. Find the equal legs of the triangle, which is the radius of the circle.

I don't see the correct answer in any of the variants. I believe the red circle on your sketch is the correct one.
 
$(x-2)^2 + (y-1)^2 = r^2$

$AB = 8 \implies r >4 \implies r^2 > 16$
 
Okay, thank you for all your answers. :)