MHB [ASK] Exact Measure Using Two Bottles

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To measure exactly 4 liters using a 5-liter and a 3-liter bottle, fill the 5-liter bottle and pour into the 3-liter bottle until it is full, leaving 2 liters in the 5-liter bottle. Empty the 3-liter bottle, then transfer the remaining 2 liters from the 5-liter bottle to the 3-liter bottle. Refill the 5-liter bottle and pour into the 3-liter bottle until it is full again, which will leave exactly 4 liters in the 5-liter bottle. This method demonstrates how to achieve various measurements using the two bottles effectively.
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Someone wants to take 4 liters of water, but he only has two 5-liters and 3-liters bottles. How is he able to measure 4 liters with only those bottles?
 
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You can in fact make any integer 1–8 litres of water using just those two bottles.

1 litre:
  • Fill up the 5ℓ bottle, and use it to fill up the 3ℓ bottle.
  • Empty the 3ℓ bottle, and transfer the contents of the other bottle to it.
  • Fill up the 5ℓ bottle again, and use to top up the 3ℓ bottle.
  • Empty the 3ℓ bottle, and fill it up again with the contents of the other bottle. There will now be exactly 1 litre of water in the 5ℓ bottle.

2 litres:
As for the 1-litre scenario, but stop after the first step. There will be exactly 2 litres of water in the 5ℓ bottle.

3 litres:
Just fill up the 3ℓ bottle.

4 litres:
As for the 1-litre scenario, but stop after the third step. There will be exactly 4 litres of water in the 5ℓ bottle.

5 litres:
Just fill up the 5ℓ bottle.

6 litres:
Fill up the 3ℓ bottle, empty it into the 5ℓ bottle, then fill up the 3ℓ bottle again. There will be a total of 6 litres of water in both bottles.

7 litres:
As for the 1-litre scenario, but after the second step just fill up the 5ℓ bottle. There will be a total of 7 litres of water in both bottles.

8 litres:
Fill up both bottles.
 
Last edited:
Thanks, Olinguito!

Btw, I have remembered when I saw you in another forum. When I was browsing old threads at MIF, I saw your account there.
 
Yes, I’m on various forums (including some non-math ones). (Nod)
 
Which non-math forums are you in?
 
I have been insisting to my statistics students that for probabilities, the rule is the number of significant figures is the number of digits past the leading zeros or leading nines. For example to give 4 significant figures for a probability: 0.000001234 and 0.99999991234 are the correct number of decimal places. That way the complementary probability can also be given to the same significant figures ( 0.999998766 and 0.00000008766 respectively). More generally if you have a value that...

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