[ASK] Find 1/(1)+1/(1+2)+1/(1+2+3)+…+1/(1+2+3+…+2009)

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SUMMARY

The series 1/(1) + 1/(1+2) + 1/(1+2+3) + ... + 1/(1+2+3+...+2009 can be simplified using the formula for the sum of the first n integers, S = n(n+1)/2. By rewriting the series, it can be expressed as S = 2(1/(1·2) + 1/(2·3) + 1/(3·4) + ... + 1/(2009·2010), which allows for easier computation of the sum. This transformation leverages the properties of arithmetic series to facilitate the addition of fractions.

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Monoxdifly
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Does anyone know how to add these fractions?
[math]\frac11+\frac1{1+2}+\frac1{1+2+3}+…+\frac1{1+2+3+…+2009}[/math]
Like my previous question, I believe this one also has something which can be canceled out, and the denominators contain arithmetic series. Can this series be used to make some sorts of shortcuts?
 
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Monoxdifly said:
Does anyone know how to add these fractions?
[math]\frac11+\frac1{1+2}+\frac1{1+2+3}+…+\frac1{1+2+3+…+2009}[/math]
Like my previous question, I believe this one also has something which can be canceled out, and the denominators contain arithmetic series. Can this series be used to make some sorts of shortcuts?

We know:

$$\sum_{k=1}^n(k)=\frac{n(n+1)}{2}$$

And so the given series becomes:

$$S=2\left(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\cdots+\frac{1}{2009\cdot2010}\right)$$
 

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