[ASK] Find 1/(1×2)+1/(2×3)+1/(3×4)+…+1/(2009×2010)

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SUMMARY

The discussion centers on the summation of the series defined by the fractions 1/(n(n+1)) for n ranging from 1 to 2009. Participants emphasize the utility of Partial Fraction Decomposition, specifically the transformation of 1/(n(n+1)) into the form 1/n - 1/(n+1). This approach allows for the cancellation of terms in the series, leading to a simplified calculation of the total sum. The final result of the series can be derived using this method, confirming its effectiveness in solving the problem.

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Monoxdifly
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Does anyone know how to add these fractions?
[math]\frac1{1\times2}+\frac1{2\times3}+\frac1{3\times4}+…+\frac1{2009\times2010}[/math]
I believe making them in [math]\frac12+\frac1{6}+\frac1{12}+….+\frac1{421890}[/math] form isn’t the correct approach.
Is there anything we can cancel out?
 
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Re: [ASK] Fracttion Addition

Monoxdifly said:
Does anyone know how to add these fractions?
[math]\frac1{1\times2}+\frac1{2\times3}+\frac1{3\times4}+…+\frac1{2009\times2010}[/math]
I believe making them in [math]\frac12+\frac1{6}+\frac1{12}+….+\frac1{421890}[/math] form isn’t the correct approach.
Is there anything we can cancel out?

What does Partial Fraction decomposition do for us? $\dfrac{1}{n\cdot(n+1)} = \dfrac{1}{n}-\dfrac{1}{n+1}$
 

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