- #1

RidiculousName

- 28

- 0

I'm trying to figure out how to solve 4

I've gotten as far as

2

2(5-9x) = 1/(3(x-2))

10 - 18x = 1/(3x-6)

But, I'm not sure how to deal with the fraction.

EDIT: swapped 4

^{5-9x}=1/(8^{x-2}) for x.I've gotten as far as

2

^{2(5-9x)}= 1/(2^{3(x-2)})2(5-9x) = 1/(3(x-2))

10 - 18x = 1/(3x-6)

But, I'm not sure how to deal with the fraction.

EDIT: swapped 4

^{5-9x}=1/(**x**^{x-2}) with 4^{5-9x}=1/(**8**^{x-2})
Last edited: