I am designing a simple truss structure...(adsbygoogle = window.adsbygoogle || []).push({});

consider a member of a truss under a compression of xN.

As x increases, the member will tend to want to buckle.

eulers strut buckling formula states that the force a member buckles at is inversely proportional to the square of the length of the member.

so halving the length will multiply this load by 4.

I'm certain this isn't a new proposition but I thought Id say it anyway...

putting an normally unloaded strut perpendicular to the midpoint of a member under compression, to effectively half the length of the member, as this unloaded strut will constrain the member and prevent it from buckling in the centre? Am i correct? obviously there will be a slight load in the perpendicular strut, but not considerable (i hope).

I hope I have explained this fairly well and i would just like some feedback as to whether this is a flawed theory? I understand it wouldnt be as effective as truly halving the length of the member but, should increase the buckling load somewhat?

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# Assisting struts under compression

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