Astrophysics question: Wire mesh radio telescope antenna

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SUMMARY

The discussion revolves around the calculation of the antenna size for a wire mesh radio telescope, specifically questioning how a 1-meter measurement was derived. The mark scheme indicates that 50mm relates to the resolving power, adhering to the Rayleigh criterion. Participants seek clarification on the application of the Rayleigh criterion equation in this context, particularly in relation to the provided problem statements and mark schemes from the January 2003 astrophysics exam papers.

PREREQUISITES
  • Understanding of the Rayleigh criterion in optics
  • Familiarity with radio telescope antenna design principles
  • Basic knowledge of resolving power in astrophysics
  • Ability to interpret physics problem statements and mark schemes
NEXT STEPS
  • Study the Rayleigh criterion equation in detail
  • Research the principles of radio telescope antenna design
  • Examine past astrophysics exam papers for practical applications
  • Learn about resolving power and its implications in observational astronomy
USEFUL FOR

Students studying astrophysics, educators teaching optics and radio astronomy, and anyone involved in the design and analysis of radio telescope systems.

bonbon22
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Homework Statement
https://downloads.umutech.net/Physics/Past_Papers/PA05/Astro/QP/physics_u5_astro_qp_jan_2003.pdf
question 3a also image below
Relevant Equations
Rayleigh criteria equation
244199

The answer says its 1 meter i don't understand how they arrived at this, The mark scheme suggests that the 50mm is the resolving power or Rayleigh criteria?

https://downloads.umutech.net/Physics/Past_Papers/PA05/Astro/MS/physics_u5_astro_ms_jan_2003.pdf
 
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bonbon22 said:
Problem Statement: https://downloads.umutech.net/Physics/Past_Papers/PA05/Astro/QP/physics_u5_astro_qp_jan_2003.pdf
question 3a also image below
Relevant Equations: Rayleigh criteria equation

View attachment 244199
The answer says its 1 meter i don't understand how they arrived at this, The mark scheme suggests that the 50mm is the resolving power or Rayleigh criteria?

https://downloads.umutech.net/Physics/Past_Papers/PA05/Astro/MS/physics_u5_astro_ms_jan_2003.pdf
anyone know very confused.
 

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