# At what velocity does the cannonball leaves the cannon?

Yeah I cannot figure this out...

## Homework Statement

.A cannon fires a cannonball 500.0m downrange when set at a 45.0o angle. At what velocity does the cannonball leaves the cannon?

Given Angle : 45
Distance: 500m
Vi : ?

## Homework Equations

dy = viy(t)+ 4.9(t)^2

## The Attempt at a Solution

Only thing I figured out is that vix = viy

and that t = 500/vicos45

Last edited: