-aux.20.The lifespan of a particular species of insect is normally distributed

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Discussion Overview

The discussion revolves around the lifespan of a species of insect that is normally distributed, with a specific focus on determining the time $t$ after which $90\%$ of the insects die. Participants explore the interpretation of the problem statement and the calculations involved in finding the value of $t$ based on the given mean and standard deviation.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested, Mathematical reasoning

Main Points Raised

  • One participant states the lifespan is normally distributed with a mean of $57$ hours and a standard deviation of $4.4$ hours, and calculates $t$ based on the assumption that $90\%$ of the insects die after $t$ hours.
  • Another participant questions the ambiguity in the problem statement, suggesting different interpretations of what "$90\%$ of the insects die after $t$ hours" could mean, which could lead to different answers.
  • A third participant provides a different $z$-score value, suggesting it is closer to $1.28$ rather than $1.29$, and mentions a more precise value from a computer calculation.
  • Subsequent replies refine the calculation of $t$ using the adjusted $z$-score, leading to a value of approximately $63$ hours.
  • Participants discuss the limitations of using standard z-tables and suggest alternatives like using Excel for more precise calculations.
  • One participant expresses frustration with the use of z-tables and shares a method for obtaining a more accurate $z$-score using Excel.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the interpretation of the problem statement, with multiple competing views on what is meant by "$90\%$ of the insects die after $t$ hours." There is also variation in the $z$-score values used in calculations, indicating a lack of agreement on the precise statistical approach.

Contextual Notes

There are unresolved assumptions regarding the interpretation of the problem statement, which affects the calculations. Additionally, the reliance on different sources for $z$-score values introduces variability in the results.

karush
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The lifespan of a particular species of insect is normally distributed with a mean of $57$ hours and a standard deviation of $4.4$ hours.
$90\%$ of the insects die after $t$ hours.
Represent this information on a standard normal curve diagram,
indicating clearly the area representing $90\%$.
$.9$ on the z-table $\displaystyle \approx z=1.29$. so from W|A
Find the value of t.
$\displaystyle\frac{t-57}{4.4}=1.29$ thus $t\approx 63s$
 
Last edited:
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Hi karush.

I find the problem statement a bit ambiguous: "$90\%$ of the insects die after $t$ hours."
I guess you interpreted it as "$90\%$ of the insects are dead after $t$ hours." or "$90\%$ of the insects die after $t$ hours or less."
I'm wondering if they intended: "$90\%$ of the insects die after at least $t$ hours."
In that case you'd get a different answer, but I'm not sure if that's what was intended.
Perhaps you can clarify.

Anyway, for the rest your calculation is fine.

One correction: I don't think they die after 63 seconds which would be a ridiculously short lifespan. Shall we make it hours?
 
My only contribution is according to my table the $z$-score is closer to 1.28, and the computer gives an approximate value of 1.28155.
 
ok, i got the bugs out of it.

$\displaystyle\frac{t-57}{4.4}=1.28155$

$t = 62.6432 or \approx 63h$

using the wiki z-table which only goes to hundredths; is there a W|A calculator for getting more digits?

yes i wasn't sure about what they were asking? maybe it should look this

https://www.physicsforums.com/attachments/1150
 
Last edited:
I used the command in W|A:

erf(z/sqrt(2))=2(0.4)

and it returns:

$$z\approx1.28155$$
 
karush said:
using the wiki z-table which only goes to hundredths; is there a W|A calculator for getting more digits?

I have given up on W|A for statistical calculations.
Instead I recommend Excel.
Type in a cell "=NORMSINV(0.9)" and you'll get your result $1.281551566$.
 
well that is good to know. Its hard to use a table, often choosing the one really not the closest.

thank again. gems of know how every time...
 

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