Look at the following derivation:(adsbygoogle = window.adsbygoogle || []).push({});

##

p=\frac{im}{\hbar}[H,r]

##

if ##H|\psi\rangle=E|\psi\rangle##, then

##

\langle \psi|p|\psi \rangle = \frac{im}{\hbar}\langle \psi|Hr-rH|\psi \rangle = \frac{im}{\hbar}\langle \psi|r|\psi \rangle(E-E)=0

##

What's wrong with my derivation or it is true that average momentum of energy eigenstates is always zero?

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# Average momentum of energy eigenstates is always zero?

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