Average Recoil Energy of a Compton Electron

  1. 1. The problem statement, all variables and given/known data

    For an assignment question, I am trying to work out an approximate formula for the average recoil energy of an electron involved in a Compton scattering event (averaged over all scattering angles theta). Note that there are other ways to do this problem than the formula I use below involving the scattering cross sections and whatnot, but we are supposed to use the formula below and then compare our answer to the cross section method to see how they differ.

    2. Relevant equations

    We are to use the equation for the recoil energy of a Compton electron as a function of the photon scattering angle theta:

    [tex]

    \frac{E_r_e_c_o_i_l}{h\nu} = \frac{\epsilon(1-cos\theta)}{1+\epsilon(1-cos\theta)}

    [/tex]

    I want to find

    [tex]
    \frac{\bar{E_r_e_c_o_i_l}}{h\nu}
    [/tex]

    I.e - the energy of the recoil electron (normalised to the incoming photon energy) averaged over all possible scattering angles

    3. The attempt at a solution

    I was thinking that the way to go about this was to do the following:

    [tex]
    \frac{\bar{E_r_e_c_o_i_l}}{h\nu} = \frac{\displaystyle\int^\pi_0 F(\theta)\,d\theta}{\displaystyle\int^\pi_0 \,d\theta}
    [/tex]

    Where


    [tex]

    F(\theta) = \frac{\epsilon(1-cos\theta)}{1+\epsilon(1-cos\theta)}

    [/tex]

    The problem is, I have absolutely no idea how to even start doing this integral! A substitution? Integration by parts? Manipulation using trig identities, and then one or both of the above?

    Any guidance or direction from a more mathematically able mind than my own would be much appreciated... This problem is killing me.
     
  2. jcsd
  3. You will need to take the integral over the solid angle, so you need this:

    [tex]\int d\Omega = \int \int sin(\theta) d\theta d\phi[/tex]

    So do the same as before, except use the integral over the solid angle instead. Then use substitution and integration by parts.
     
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