- #1

Aleolomorfo

- 73

- 4

## Homework Statement

In the inverse Compton scattering there is a particle, with energy ##E## in the laboratory frame and mass at rest ##m##, which collide head on with a photon with energy ##E_\gamma##. Finding the maximum energy the photon can have after being scattered.

## The Attempt at a Solution

My result for the energy of the scattered photon is:

$$E'_\gamma=E_\gamma\frac{E+\sqrt{E^2-m^2}}{E_\gamma+E-\cos{\theta}(E_\gamma-\sqrt{E^2-m^2})}$$

##\theta## is the scattering angle of the photon (I hope the formula is correct without calcus mistakes)

My doubt is about the condition to impose in order to get the maximum energy. The energy is maximum when the denominator is minimum and so the condition is on ##\cos{\theta}##. I would impose ##\cos{\theta}=1## and so ##\theta=0##, but my sixth sense is telling me that this is not the correct answer.