Average Velocity Graph: Determine its Values

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SUMMARY

The discussion focuses on calculating average velocity from a provided graph. The correct average velocities between specified time intervals are determined to be 1.6 m/s for the interval from t = 25.0 s to t = 30.0 s, and 0.67 m/s for the interval from t = 35.0 s to t = 50.0 s. The initial calculations of 1 m/s and 2/3 m/s were incorrect due to misinterpretation of displacement values. Participants emphasized the importance of accuracy in measurements and sign conventions in physics calculations.

PREREQUISITES
  • Understanding of average velocity calculations
  • Familiarity with displacement and time concepts
  • Basic knowledge of graph interpretation in physics
  • Experience with online homework tools like Webassign
NEXT STEPS
  • Review the concept of average velocity and its formula
  • Learn how to accurately interpret displacement from graphs
  • Study the significance of sign conventions in physics
  • Explore troubleshooting common errors in online homework platforms like Webassign
USEFUL FOR

Students studying physics, educators teaching kinematics, and anyone using online homework systems for physics problem-solving.

Toxage
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Graph :

http://img354.imageshack.us/my.php?image=physicslp1.png

or

http://www.turboimagehost.com/p/766378/physics.JPG.html

Questions:

Determine its average velocity between the following times.

1. t = 25.0 s and t = 30.0s

2. t = 35.0 s and t = 50.0 s

The Attempt at a Solution



average velocity = overall displacement / overall time

1. 6m/5 sec = 1. m/s

2. 10 m / 15 s = 2/3 ms

My teacher uses on online homework program called Webassign, and both of these showed up as wrong. I don't know why. If anyone could help me that would be awesome.
 
Last edited:
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Toxage said:
Graph :

http://img354.imageshack.us/my.php?image=physicslp1.png

or

http://www.turboimagehost.com/p/766378/physics.JPG.html

Questions:

Determine its average velocity between the following times.

1. t = 25.0 s and t = 30.0s

2. t = 35.0 s and t = 50.0 s


The Attempt at a Solution



average velocity = overall displacement / overall time

1. 6m/5 sec = 1. m/s

2. 10 m / 15 s = 2/3 ms

My teacher uses on online homework program called Webassign, and both of these showed up as wrong. I don't know why. If anyone could help me that would be awesome.

On the first it looks like 8m not 6m. It will likely not think it's good if off by 10%.

Check your sign on the second one.
 

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