Convergence of a Series: How to Determine its Value?

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Homework Help Overview

The discussion revolves around the convergence of an alternating series defined as the sum from 1 to infinity of [(-1)^n * n / (n^2-4n-4)]. Participants are exploring methods to determine whether the series converges or diverges, and if it converges, to what value.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the use of the ratio test and the alternating series test (AST) to assess convergence. There is uncertainty about the implications of the limit being zero and whether this indicates convergence to a specific value. Questions arise regarding the need for further analysis to determine the series' convergence value and the distinction between absolute and conditional convergence.

Discussion Status

Some participants suggest that the series converges based on the alternating series test, while others question the interpretation of the limit and the necessity of additional steps to find the actual value of convergence. There is acknowledgment of confusion regarding the application of the ratio test and the conditions for convergence.

Contextual Notes

Participants note that the problem is presented in an online format, which may impose specific constraints or expectations for the solution. There is also mention of the need to clarify the results from the ratio test as part of the homework requirements.

MeMoses
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Homework Statement


I'm not sure how to do the notation on here but. Does this series converge or diverge. If it converges, then to what value.
The series: Sum from 1 to infinity of [(-1)^n * n / (n^2-4n-4)]


Homework Equations


It tells me to use the ratio test


The Attempt at a Solution


I used the ration test and got the limit to equal 1 which is inconclusive. I used the alternating series test to find that it converges, but how do I figure what it converges to and whether it is absolute convergence or not? I'm new to series so this is a little confusing. Any help is appreciated
 
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In LaTeX form, this is what your equation appears like:
\sum^{\infty}_{n=1} \frac{(-1)^n n}{ (n^2-4n-4)}
Since there is an alternating sign and you need to find the series, i believe you need to use AST.

The conditions that must be satisfied for the series to converge:a_n&gt;0<br /> \\\lim_{n \rightarrow \infty} a_n=0<br /> \\a_{n+1} \leq a_nwherea_n=\frac{n}{n^2-4n-4}Indeed, the series converges.
\lim_{n \rightarrow {\infty}} \frac{n}{n^2-4n-4}=\lim_{n \rightarrow {\infty}} \frac{1/n}{1-4/n-4/n^2}
I would say it converges to 0?

To test for absolute or conditional convergence, test if the absolute value of the original series converges or not:
\sum^{\infty}_{n=1} \left|\frac{n}{ (n^2-4n-4)}\right|
 
Last edited:
How can you say it converges at 0? When the limit of An is 0 doesn't that just mean that the series converges? Wouldn't I need to write it as a function somehow and take the limit of that to find the convergence? This is an online problem and 0 isn't correct
 
Sorry I was reading the questing wrong. It was asking for my results from the ratio test which explains a lot.
 
MeMoses said:
How can you say it converges at 0? When the limit of An is 0 doesn't that just mean that the series converges?
No, it means the series may converge. It may still diverge as well. In any case, what sharks implied above is wrong, as you noted.

Wouldn't I need to write it as a function somehow and take the limit of that to find the convergence? This is an online problem and 0 isn't correct
Yes, generally you'll need to find another way to figure out what a series converges to, if it indeed converges.
 

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