Balanced Equation: 2S(s)+3O2(g) ----> 2SO3(g): Correct Interpretation

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The balanced chemical equation 2S(s) + 3O2(g) → 2SO3(g) represents the reaction of sulfur and oxygen to form sulfur trioxide. The incorrect interpretation identified in the discussion is option c, which states that 2 g S + 3 g O2 → 2 g SO3. This is incorrect because the coefficients in the equation represent moles, not grams. The correct interpretations are options a and b, which accurately reflect the mole relationships in the reaction.

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Which of the following is an INCORRECT interpretation of the balanced equation shown below?

2S(s) + 3O2(g) ----> 2SO3(g)



a.) 2 mol S + 3 mol O2 ----> 2 mol SO3
b.) 2 atoms S + 3 molecules O2 ----> 2 molecules SO3
c.) 2 g S + 3 g O2 ----> 2 g SO3
d.)none of the above
 
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So what do you think?

Note: this question should have been posted in the Homework Forum.
 
Do you understand that different elements have different atomic masses?
 
i think that the answer is c?
 
Last edited:
ProblemSets said:
i think that the answer is c?
...Why? ...
 
coefficients symbolize the number of moles so A would be correct.

Then I am not 100% sure about B cause the molecules seem to be right but I am not sure about the atoms of S and if that is a correct interpretation.

And for C, I don't think that the coefficients can stand for grams cause there are multiple grams in a mole.

How is my thinking?
 

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