Balancing Chemical Equations: KI + KClO3 + H2SO4 and KMnO4+NaNO2+KOH

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SUMMARY

The discussion focuses on balancing two chemical equations: KI + KClO3 + H2SO4 yielding I2 + KCl + K2SO4 + H2O, and KMnO4 + NaNO2 + KOH yielding K2MnO4 + NaNO3 + H2O. The user expresses difficulty in achieving balance for these equations. The balanced coefficients for the first equation are 6, 1, 3 for the reactants and 3, 1, 3, 3 for the products. For the second equation, the coefficients are 2, 1, 2 for the reactants and 2, 1, 1 for the products.

PREREQUISITES
  • Understanding of chemical reaction balancing
  • Familiarity with stoichiometry
  • Knowledge of oxidation-reduction reactions
  • Basic skills in manipulating chemical equations
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  • Study the principles of balancing chemical equations
  • Learn about stoichiometric coefficients and their significance
  • Explore oxidation states in redox reactions
  • Practice with additional examples of balancing complex chemical reactions
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Chemistry students, educators, and anyone seeking to improve their skills in balancing chemical equations and understanding stoichiometry.

htk
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KI + KClO3 + H2SO4=> I2 + KCl + K2SO4 + H2O

KMnO4+NaNO2+KOH=>K2MnO4+NaNO3+H2O

These two equations make me crazy. :rolleyes: I try to balance it, but it won't work for me. Please help. Thank you! :biggrin:
 
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6,1,3 -> 3,1,3,3
2,1,2 -> 2,1,1
 

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