Balancing N2O & O2 to Create NO2 - Check Your Answer Here!

  • Context: Chemistry 
  • Thread starter Thread starter Jules18
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Discussion Overview

The discussion revolves around a chemistry homework problem involving the reaction of nitrous oxide (N2O) and oxygen (O2) to produce nitrogen dioxide (NO2). Participants are trying to determine the limiting reactant and how many moles of each reactant will remain after the reaction.

Discussion Character

  • Homework-related
  • Debate/contested

Main Points Raised

  • One participant states that the limiting reactant should be the 8 moles of O2 based on a method of dividing the number of moles by the coefficients in the balanced equation.
  • Another participant expresses confusion, noting that the answer key indicates that O2 is in excess, which contradicts their understanding.
  • A participant emphasizes that they have their own answer but refrains from sharing it to avoid influencing others.
  • There is a discussion about trust among students, with one participant feeling offended by being labeled as lazy, while another clarifies that their comment was about a general trend rather than a personal accusation.

Areas of Agreement / Disagreement

Participants do not reach a consensus on which reactant is limiting, as there are conflicting interpretations of the problem and the answer key. The discussion remains unresolved regarding the correct identification of the limiting reactant.

Contextual Notes

Participants express uncertainty about the answer key's correctness and the method for determining the limiting reactant, indicating a potential misunderstanding of stoichiometric principles.

Jules18
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Homework Statement



2 N2O + 3 O2 = 4 NO2

If 6 moles of N2O and 8 moles of O2 react to produce as much NO2 as possible, how many moles of which reactant will remain at the end of the reaction?

The Attempt at a Solution



I got an answer, but I don't want to sway anyone so I won't say what it was. I just want to check my answer with someone else's o:) o:)
 
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The limiting reactant should be the 8 moles of O2.

The way I learned to find out which number of moles is limiting is to divide each number of moles of reactant by the coefficient of the reactant in the balanced equation. The one with the smallest number is the limiting reactant.
 
i know, right?? that's what I thought but the answer key says the excess is supposed to be O2.
that's why I posted this - I'm pretty sure it's wrong but I needed a second opinion
 
Jules18 said:
I got an answer, but I don't want to sway anyone so I won't say what it was.

You may safely give your answers, we are not that easy to confuse. But we are easily doubting someone who says so really did anything - way too often lazy students try to play that trick.

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I'm not a lazy student! How dare you, good sir.
 
Borek said:
You may safely give your answers, we are not that easy to confuse. But we are easily doubting someone who says so really did anything - way too often lazy students try to play that trick.

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buffer calculator, concentration calculator
pH calculator, stoichiometry calculator

You sir, are a douche.

lol anyways it's fine, Bohrok's answer was enough of a reassurance.

You should trust students on here a little more. Most of the lazy ones don't even bother to look for help. I really, really hate being called lazy, it's a thing.
 
I have not said YOU are the lazy student. I wrote that we often see people stating "I did it" when they have not. We see it so often we don't believe even when it is a just truth.

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