Balancing Redox Reaction: FeS2+Na2O2→Na2FeO4+Na2SO4+Na2O"

[DottZakapa]

Homework Statement

Balance redox reaction

Relevant Equations

FeS2+Na2O2->Na2FeO4+Na2SO4+Nao

FeS₂+Na₂O₂->Na₂FeO₄+Na₂SO₄+Na₂O

Fe²⁺ --->Fe⁺⁶+4e^-
2S^-1 --->2S⁺⁶+14e^-
2O^- + 2e^- ---> 2O
The first two have a total of 18 electrons so
In order to balance the electrons i should multiply by 9 the third semireaction
(2O^- + 2e^- ---> 2O^-2)x9

now this 9 is going to multiply the left hand in the semi reaction equation, isn't also multiplying the right hand side?

 

[BvU]

It is, yes. But is this really the way you want to handle this ? Why not solve for $$a\text{A}+b\text{B}\rightarrow c\text{C}+d\text{D} + e\text{E}\ ?$$

 

[chemisttree]

...now this 9 is going to multiply the left hand in the semi reaction equation, isn't also multiplying the right hand side?

Yes

 

[DottZakapa]

sorted
i multiply by 9 just the right hand side
while i balance as usual the left hand side due to the multiple presence of the oxygen