Balancing redox reactions occurring in acidic solutions

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Discussion Overview

The discussion focuses on balancing redox reactions occurring in acidic solutions, specifically addressing the reaction between lead dioxide and iodide ions. Participants explore the steps involved in balancing the reaction, including the identification of half-reactions and the balancing of atoms and charges.

Discussion Character

  • Homework-related

Main Points Raised

  • One participant presents a structured attempt at balancing the redox reaction, outlining the half-reactions for reduction and oxidation.
  • Another participant challenges the proposed oxidation half-reaction, indicating disagreement with the balancing of iodide ions.
  • A participant expresses confusion regarding the process of inserting and balancing the number of electrons in the half-reactions.
  • Another participant suggests that balancing should start with atoms before using electrons to balance charge, emphasizing that differing charges indicate an unbalanced equation.

Areas of Agreement / Disagreement

There is no consensus on the correctness of the proposed balancing steps, as participants express differing views on specific aspects of the balancing process.

Contextual Notes

Participants have not fully resolved the steps for balancing the reaction, and there are indications of missing assumptions regarding the balancing of charges and the treatment of electrons.

shikam08
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Homework Statement


Balance the following redox reactions occurring in an acidic solution.


Homework Equations


PbO2(s)+I-(aq)---->Pb2+(aq)+I2(s)


The Attempt at a Solution


1.) half reactions:
a.) reduction: I-(aq)----->I2(s)
b.) oxidation: PbO2(s)------>Pb2+(aq)
2.) balance Oxygens and Hydrogens
PbO2+4H+------>Pb2++2H2O
3.) add electrons to balance equations
a.)PbO2+4H++4e---->Pb+2+2H2O
b.) 4I--->4I2+4e-
4.) cancel out the electrons and combine the half reactions
PbO2+4H++4I--->Pb2++4I2+2H2O
 
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shikam08 said:
b.) 4I--->4I2+4e-

Nope.
 
Last edited by a moderator:
I don't understand how to insert the number of electrons on both sides to balance the equations and cancel out the electrons.
 
Balance atoms first, then use electrons to balance charge in half reaction. As long as charge on both sides is different, equation is not balanced.
 
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