Balancing Redox Reactions in Acid and Basic Solutions

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SUMMARY

This discussion focuses on the balancing of redox reactions in acid and basic solutions, emphasizing the physical implications of using different media. In acidic conditions, the reaction is balanced using H+ ions, as demonstrated in the equation MnO4- + 8H+ + 5e- → Mn2+ + 4H2O. Conversely, while it is technically possible to balance the same reaction in basic conditions using water and OH- ions, it is less practical, as shown in the alternative equation MnO4- + 4H2O + 5e- → Mn2+ + 8OH-. The choice of medium affects the balancing approach due to the availability of reactants and the reaction's feasibility.

PREREQUISITES
  • Understanding of redox reactions and their components.
  • Familiarity with acid-base chemistry, specifically the role of H+ and OH- ions.
  • Knowledge of stoichiometry in chemical equations.
  • Basic grasp of chemical equilibrium concepts.
NEXT STEPS
  • Study the principles of balancing redox reactions in various media.
  • Learn about the role of H+ and OH- ions in chemical reactions.
  • Explore examples of redox reactions in both acidic and basic environments.
  • Investigate the concept of reaction feasibility and its dependence on medium conditions.
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Chemistry students, educators, and professionals interested in understanding the nuances of redox reaction balancing in different pH environments.

sbhit2001
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I understand the concept of balancing chemical equations but in the case of redox reactions I don't understand the physical meaning of balancing in acid medium and balancing in Basic medium. Sure, I know how to balance the equation but I want to know what it means physically. Why do we need to balance differently for different media? How is the medium related to the balancing of an equation? Can someone please throw some light on this?
 
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To some extent there is no difference, it is just a matter of what is available in the solution (and sometimes of what is more convenient). When we balance reaction that occurs in a very low pH (like permanganate getting reduced to Mn(II)) it is more logical to balance hydrogen and oxygen using H+ and water:

MnO4- + 8H+ + 5e- → Mn2+ + 4H2O

than it would be to balance them with water and OH- (even if technically it is possible:

MnO4- + 4H2O + 5e- → Mn2+ + 8OH-

and the stoichiometry would be correct, just the reaction doesn't proceed like that).
 

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