Balancing Teeet Totter: Lever Arm Calculation

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Homework Statement



Two children whose masses are 35kg and 55kg are on a playground "teeet totter" which is 3.0m long. Where must the fulcrum be placed so that the children will balance?
(35kg on left, 55kg on right)

Homework Equations



sum of T=0

The Attempt at a Solution


I started with T=0=F(left)L(left)-F(right)L(right)
The two lever arms must add to be 3.0m so L(left)=3.0m-L(right). Through some algebra i got the equation into terms of L(right):
L(right)=(3m)(Fleft)/(2(Fright))
I get the right lever to be .95m, but is supposed to be between 1-1.5

Where am i going wrong??
Thanks
 
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Start simple.

Let the distance from one end be x metres, then the distance from the fulcrum to the other end is (3-x)metres.

For it to be balances the resultant torque about the fulcrum must be zero.
Can you set up the equation now?
 
This is all assuming the teeter totter is massless.
 
Last edited:
teacher said you can ignore mass of teeter totter.
And to rock.freak667, that's exactly how i started. I got 0=(x-3)(Fleft)-(X)(Fright)...
 
Clockwise moment about pivot=(33gx) Nm
Anti-clockwise moment about pivot=55g(3-x) Nm

For balance

55g(3-x)=33gx


Are you sure you did the algebra correctly?

55(3-x)=33x
165-55x=33x
88x=165
 
r*m = r*m
 

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