- #1

- 212

- 0

a) Find the direction in which ball A moves after the collision.

b) Can you determine the speed of A from the information given? Explain

So, conversation of momentum

lets let ball A have mass m, and ball B have mass M

mVai + Mvi = mVaf + Mvf

0 + Mv = mVaf + (1/2)Mv

(1/2)Mv = mVaf

Vaf = (Mv)/2m

It seems I need to solve B before solving A

Since ball B moves at a right angle to its initial velocity, if we say it was moving only in the x direction initally, it now has no x coordinate of velocity, so all of its x momentum will be transferred to ball A

so cosx = v/[(Mv)/2m]

cosx = 2mv/Mv

cosx = 2m/M

x = arccos(2m/M)

Have I done all of this right?

Thanks