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Ball rolling down a segment then up a parabolic segment

  • Thread starter talaroue
  • Start date
  • #1
303
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Homework Statement


A 181 g ball is released from rest H=5.19 m above the bottom of the track shown in Figure. It rolls down a straight 21° segment, then back up a parabolic segment whose shape is given by y=x2/4, where x and y are in m. How high will the ball go on the right before reversing direction and rolling back down?
C10P81.jpg


Homework Equations


Ki+Ui=Kf+Uf
K=mv^2/2


The Attempt at a Solution


I am not sure how to start this because everytime i go to one direction i hit a dead end.
At the begining it has both Ki=0 and Ui=0 correct?
Then at the final it has Kf and Uf right?
 

Answers and Replies

  • #2
303
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Here is my work but I don't even think I am on the right track......

This is for rolling down incline
Physics7.jpg



This is for rolling up the parabola
Physics8.jpg

EDIT: I put the wrong dominator in for the very last part when calculating Y it should be 4, but that anwser did not work either
 
  • #3
303
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WOOOOOOW I am so sorry for wasting everyones times the parabola made me over think this equation since Ki+Ui=Kf+Kf.....energy would force the ball up the same height as it began.
 
  • #4
Cyosis
Homework Helper
1,495
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The question gave you additional information to deceive you. Realizing this in the end only makes you understand energy conservation better. It's hardly wasting anyone's time.
 
  • #5
303
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Yeah, I see what you mean but I didn't need to make a thread after.
 

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