A man standing 31 m from the base of a vertical cliff throws a ball with a speed of 38 m/s aimed directly at a point 5 m above the base of the cliff.
Here is a link to the diagram....
How long does it take the ball to reach the cliff?
First off i tried to find the time to get to the max height:
v = v(initial)+at
Then I found the max height:
x(final) = x(initial) + v(initial)t + 0.5at^2
x(final) = 0 + 38(3.877) + 0.5(-9.8)(3.877^2) x(final) = 73.67
This really does not look right to me though. If it is then would I have to find the time it drops from the max height to 5m? Is there anyway of finding the y component?
Last edited by a moderator: