Balmer Series and Atomic Absorbtion/Emission

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SUMMARY

The discussion centers on the Balmer series of hydrogen, specifically the relationship between absorption and emission spectra. When an electron transitions from the n=1 level to n=3, it absorbs red light at approximately 656nm. Subsequently, when it drops from n=3 to n=2, it emits red light at the same wavelength. The confusion arises from the expectation that the electron must return to n=1 to emit the same red light, which is clarified as a misunderstanding of the transitions involved.

PREREQUISITES
  • Understanding of atomic energy levels and electron transitions
  • Familiarity with the concept of absorption and emission spectra
  • Knowledge of the Balmer series in hydrogen
  • Basic principles of light and wavelength measurement
NEXT STEPS
  • Study the Balmer series transitions in detail, focusing on energy level diagrams
  • Research the principles of atomic absorption spectroscopy
  • Explore the relationship between wavelength and energy in photon interactions
  • Learn about other series in hydrogen, such as the Lyman and Paschen series
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Students of physics and chemistry, educators explaining atomic theory, and anyone interested in spectroscopy and the behavior of hydrogen atoms.

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Homework Statement



This isn't a homework question, but I will try and follow the template.

I am confused about the relationship between the absorption and emission spectrums for hydrogen. I was taught that in the balmer series for hydrogen, when an electron moves from the n=1 level to n=3, and then drops from n=3 to n=2 it emits red light. I was also told that the absorption spectrum would have a black line at about 656nm and a red line on the emission spectrum in the same location. It was explained that it absorbed red light, so it must emit that light when the electrons fall to a lower level.

What I don't understand is how red light absorbed could bump the electron from n=1 to 3, while dropping from n=3 to 2 would release the same light. Wouldn't it have to drop back to n=1 to emit this same red light?

Thanks!

Homework Equations



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The Attempt at a Solution



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What I don't understand is how red light absorbed could bump the electron from n=1 to 3, while dropping from n=3 to 2 would release the same light. Wouldn't it have to drop back to n=1 to emit this same red light?
Yes it would. It looks like the description got garbled.
 

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