Banking corner with sin θ > 1 in centripetal force calculation

[Physics_Student101]

hey guys I am having trouble with a banking problem i keep getting a sin theta value of 2 therefore i can't find the angle required, any ideas where I am going wrong, below is a copy of my formulas
Fnet = (MV^2) / R

Fnet = (1000*16.67^2) / 10

Fnet = 27788.89 N

Fc = Mac

Ac = V^2 / R

Ac = 16.67^2 / 10

Ac = 27.78889 ms ^ -2

Therefore

Fc = Mac

Fc = 1000 * 27.78889

Fc = 27788.89 N

G sin Ө = v^2 / R

9.8 sin Ө = 16.67^2 / 10

9.8 sin Ө = 27.78889

sin Ө = 27.78889 / 9.8

sin Ө = 2.836

 

[mukundpa]

Have you gone through the text? I think your concept is not cleare. How you have written
G sin Ө = v^2 / R

 

[Physics_Student101]

im not sure what you mean, however the squares used to be a theta symbol if that's what you mean they just didnt convert into the forum.

 

[mathmike]

what is the question and maybe we can help you better

 

[Physics_Student101]

i need to work out how banking a corner can help to increase road safety, using circular motion, friction etc... i have a car traveling at 60 km/h with a mass of 1000kg, the speed is allowed to vary but the mass must stay the same...

 

[mukundpa]

In this case the ideal situation is such that the sideway friction force is zero.
The component of normal reaction will provide the necessary centripetal force.
Resolve normal reaction in horizontal and vertical direction.

 

[Physics_Student101]

how would i work out theta in this case?

 

[mukundpa]

Draw a diagram and indicate the forces you will find

N cosq = mg (q is for theeta)
N sinq = mv^2/R
gives tanq = V^2/gR

 

[Physics_Student101]

what does the character N stand for?

 

[mukundpa]

N stands for the normal reaction of the road which is normal to the roas and makes and angle 90 - q degree with the horisontal and q with upward vertical.

Sorry for late, I was out of station.