Baryon quark model: just a question

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Discussion Overview

The discussion revolves around the symmetry of the spatial part of the wavefunction for the lightest baryons, particularly in the context of the quark model. Participants explore theoretical aspects related to the wavefunction's symmetry, energy states, and implications of the Pauli principle.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant notes that the spatial and spin parts of a baryon wavefunction must be symmetric under the interchange of any two quarks, referencing the Pauli principle and the requirement for baryons to be colorless.
  • Another participant states that the lowest energy state of any system generally has no nodes, which leads to the conclusion that the ground state has no internal or total orbital angular momentum.
  • A later reply suggests that while the wavefunction may be spherical, it does not necessarily have to be completely spherical, as the distances between quarks can vary.

Areas of Agreement / Disagreement

Participants express differing views on the exact nature of the spatial wavefunction's symmetry, with some suggesting it is spherical while others indicate it may not be completely spherical due to varying distances between quarks. The discussion remains unresolved regarding the precise characterization of the wavefunction.

Contextual Notes

There are limitations in the discussion regarding the assumptions about the wavefunction's symmetry and the implications of quark distances, which are not fully explored or defined.

Jake-Blues
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I'm in trouble on answer to this question: "Wich is the (most probable) symmetry of the spatial part of the wavefunction for the lightest baryons? Why?"

I know that the spatial and spin parts of a baryon wavefunction must be simmetric under an interchange of any two quarks (this is an assumption on the quark static model, at least for the lightest baryons: the Pauli principle is not violated because there's the colour degree of freedom: to be "colourless" a baryon must be antysimmetric on the colour degree of freedom, so his "total" wavefunction results antysimmetric), and i also know that the spatial part in the lightest baryons has l=0, but I'm not able to motivate that answer exactly.

What i am forgetting?
Someone can help me?

Sorry for my english.
 
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The lowest energy state of any system generally has no nodes.
Nodes introduce more curvature into the wave function which increases the energy. This makes the state with no internal or total orbital angular momentum the ground state.
 
Meir Achuz said:
The lowest energy state of any system generally has no nodes.
Nodes introduce more curvature into the wave function which increases the energy. This makes the state with no internal or total orbital angular momentum the ground state.




Then, talking about symmetry of the spatial part of the wavefunction, it's a spherical one, the most probably?

Thank you.
 
It is a three body wave function. While it has no angular momentum, it need not be completely spherical. That is, the distance between the two u quarks in a proton can be larger than that between a u land d quari.
 

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