- #1

#### devanlevin

what i did was say,

a=delta v/delta t,

since a is constant and he passed 18 m in the 4th second(ie from t3-t4) and 22 in the 5th i conclude

v(t=3.5)= 18m/s

v(t=4.5)= 22m/s

=>delta v=4m/s

delta t = 1s

=>a=4m/s^2

the using V(t)=Vo+at

V(3.5)=Vo+4*3.5

=>18=Vo+14

=>Vo=4

is this a correct calculation or am i doing something wrong somewhere?

the whole question is in kinematics and there are no other forces afecting the car.

the answer in the book says Vo=0m/s and i cannot figure out how they got to that, it might be a mistake